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I just came accross the following problem: suppose you have a string variable (stringvar) which contains text and question marks. Question marks are usually used as wildcards for single letters or numbers. So, when you want to apply some changes to the variable (here: removing the “?”), you should NOT type
replace stringvar = regexr(stringvar,"?","")
or
replace stringvar = regexr(stringvar,"`?'","")
In this case, any character of stringvar would be replaced. The variable would have no observations. Instead you have to add a backslash right in front the question mark:
replace stringvar = regexr(stringvar,"\?","")

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